Days 13, 14, 15: IPv4 Subnetting

CCNA 200-301 Study Guide: Network Fundamentals & IPv4 Subnetting

1.0 Understanding the CCNA 200-301 Exam Landscape

The Cisco Certified Network Associate (CCNA) certification is the industry benchmark for associate-level networking. Mastery of these domains is the first step toward a successful networking career.

Exam Blueprint at a Glance

Attribute

Details

Exam Code

200-301 v1.1

Duration

120 Minutes

Passing Score

Variable (scaled)

Core Knowledge Domains

2.0 IPv4 Addressing: The Foundation

An IPv4 address is a 32-bit logical identifier. It is presented in Dotted Decimal Notation (e.g., 192.168.1.1), where 32 bits are divided into four 8-bit octets.

Legacy Classful Addressing

Before CIDR, IP addresses were assigned in rigid blocks. While largely obsolete, these boundaries still inform default behaviors in Cisco IOS.

Class

First Octet Range

Default Mask

Max Usable Hosts

Original Purpose

A

1 - 126

255.0.0.0 (/8)

$16,777,214$

Global Organizations

B

128 - 191

255.255.0.0 (/16)

$65,534$

Mid-to-Large Networks

C

192 - 223

255.255.255.0 (/24)

$254$

Small Local Networks

3.0 CIDR: Modern IP Allocation

Classless Inter-Domain Routing (CIDR) replaced the rigid classful system in 1993. It allows for Variable-Length Subnet Masking (VLSM), enabling administrators to ignore class boundaries and use any prefix length (e.g., /25, /29).

Benefits of CIDR:

4.0 Mastering Subnetting Mechanics

Key Terminology

Core Formulas

  1. Total Subnets: $2^S$

  2. Usable Hosts per Subnet: $2^H - 2$

Critical Exam Tip: Always subtract $2$. Every subnet reserves the Network Address (all host bits 0) and the Broadcast Address (all host bits 1).

The Block Size (The "Magic Number")

The Block Size is the decimal value of the last bit "borrowed" in the mask.

5.0 Practical Application Scenarios

5.1 Scenario: Meet Host Requirements

Given: 192.168.1.0/24. Need: 4 subnets with ~45 hosts each.

Resulting Subnets:

  1. 192.168.1.0/26

  2. 192.168.1.64/26

  3. 192.168.1.128/26

  4. 192.168.1.192/26

5.2 Scenario: Skill Check

Problem: Find the Subnet ID for host 192.168.5.57/27.

  1. Block Size: $/27$ means the increment is $32$ ($256 - 224 = 32$).

  2. Subnet Ranges: $0, 32, 64, 96 \dots$

  3. Find the Fit: $.57$ falls between $32$ and $64$.

  4. Answer: Subnet ID is 192.168.5.32/27.

6.0 Special-Use Prefix Lengths

Prefix

Usage

Notes

/30

Traditional P2P Link

Provides $2$ usable addresses ($2^2 - 2$).

/31

Modern P2P Link

$2$ usable addresses; no separate net/broadcast (RFC 3021).

/32

Host Route / Loopback

Identifies exactly one IP address.

7.0 VLSM: Maximum Efficiency

The "Golden Rule" of Variable-Length Subnet Masking (VLSM): Always allocate address blocks starting from the largest host requirement and proceed to the smallest.

Example Allocation ($192.168.1.0/24$):

  1. LAN A (110 hosts): Needs $/25$. Assigned: 192.168.1.0/25 (Range: .0 – .127).

  2. LAN B (45 hosts): Needs $/26$. Assigned: 192.168.1.128/26 (Range: .128 – .191).

  3. LAN C (29 hosts): Needs $/27$. Assigned: 192.168.1.192/27 (Range: .192 – .223).

  4. WAN Link (2 hosts): Needs $/30$. Assigned: 192.168.1.240/30 (Range: .240 – .243).

8.0 Rapid Reference Cheat Sheet

Prefix

Mask (Last Octet)

Block Size

Usable Hosts

/24

.0

$256$

$254$

/25

.128

$128$

$126$

/26

.192

$64$

$62$

/27

.224

$32$

$30$

/28

.240

$16$

$14$

/29

.248

$8$

$6$

/30

.252

$4$

$2$

/31

.254

$2$

$2$

/32

.255

$1$

$1$




Revision #1
Created 2026-03-14 19:21:31 UTC by Tony Utter
Updated 2026-03-14 19:21:45 UTC by Tony Utter